被收簡訊費(IOS 18)

 上個月的電信費帳單，有2元是簡訊費。

就想說如何判斷發送了啥收費簡訊？

首先查ChatGPT, 說IOS 18無法只列出發送的訊息。

所以查看所有訊息，自己送出的訊息是藍色泡泡，

最上面有秀iMessage的，是走網路不另外收費。

最上面秀SMS的，似乎就要收費，

原來邀請家族的人，是要送出SMS簡訊的，

這就是那2元簡訊費。

error: git-remote-https died of signal 4 (Solved)

 

"Method https has died unexpectedly! Sub-process https received signal 4" after adding any additional repositories - Ubuntu Desktop 22.04

 

sudo GNUTLS_CPUID_OVERRIDE=0x1 apt-get update 

this works for me

according to this https://groups.google.com/g/linux.debian.bugs.dist/c/ItKoVDieSow

and you need to add ~/.bashrc with this

export  GNUTLS_CPUID_OVERRIDE=0x1 

for long-term use

 

 

Ubuntu安装aptitude，来解决软件包依赖关系的问题

sudo apt-get install aptitude

sudo aptitude update

sudo aptitude search

sudo aptitude install

OAK-D USB

 OAK-D USB

* Luxonics github

  https://github.com/luxonis/depthai

  https://github.com/luxonis/depthai-ros

  https://github.com/luxonis/depthai-hardware

* Luxonics Docs

SW

 DepthAI Tutorials

   - {https://docs.luxonis.com/software/depthai/getting-started/}[Getting Started]

   sudo wget -qO- https://docs.luxonis.com/install_depthai.sh | bash

   - {https://docs.luxonis.com/software/depthai/manual-install/}[Manual DepthAI installation]

   - {https://docs.luxonis.com/software/depthai/hello-world/}[Hello World]

HW

  -- {https://docs.luxonis.com/hardware/platform/deploy/usb-deployment-guide/}[USB deployment guide]

   - {https://docs.luxonis.com/hardware/platform/deploy/to-rpi/}[Deploy with Raspberry Pi]

* turtlebot4 manual

sensor/OAK-D 

https://turtlebot.github.io/turtlebot4-user-manual/software/sensors.html#oak-d

install/run

   # install

   sudo apt install ros-humble-depthai-ros

   # run

   ros2 launch depthai_examples mobile_publisher.launch.py

   # AI examples are available on the DepthAI github.

   # To view the images from these examples you will need to ssh into the robot with a -X flag:

   ssh -X ubuntu@10.42.0.1

Python3的py script呼叫其它的py script並執行

Ref: https://stackoverflow.com/questions/1186789/how-to-call-a-script-from-another-script

File test1.py:

print "test1.py"

File service.py:

import subprocess

subprocess.call("test1.py", shell=True)

The advantage to this method is that you don't have to edit an existing Python script to put all its code into a subroutine.

Documentation: Python 2, Python 3

(當呼叫的py script是跟使用者有輸入輸出的互動時，

subprocess.call可以使得跟直接執行另一個py一樣)

Ref: https://stackoverflow.com/questions/51928521/eoferror-when-starting-with-subproccess

EOFError when starting with subproccess

You are using subprocess.Popen which is a by default non blocking, piece of code, hence You program cursor moves rather than waiting for the input from the user. But what you need is a code which is blocking your program cursor. subprocess.call exactly does it. It would be waiting for the other command to execute completely.

You need to use subprocess.call to solve your problem. Just change your script2 file with this

import subprocess
p = subprocess.call(["python", "abca.py"])

You can read more about the difference between subprocess.Popen and subprocess.call in this answer. Which describes when to use which command and the difference between them

Important Note:

If your script (a.py) contains a continuous loop waiting for user input

(as shown in your code),

subprocess.run() will not be able to handle it properly

because it doesn't support interactive input.

If you need to execute a script that requires user input,

you might want to use subprocess.Popen() instead,

as it allows more control over the standard input/output.

# Run the Python script a.py

result = subprocess.run(['python3', 'a.py'], capture_output=True, text=True)

# Print the output from the script

print(result.stdout)

print(result.stderr)

# a.py:

while True: print("AAA") print("BBB") print("CCC") user_input = input("Enter something (or 'exit' to quit): ") if user_input.strip() == 'exit': break print(f"You entered: {user_input}")